# Solving Equilibrium Problems Because the equilibrium constant is small, we know that x will be rather small compared to 0.124, so the above relation can be approximated by which gives x = 0.0225.To see how good this is, substitute this value of x into the denominator of the original equation and solve again: This time, solving for x gives 0.0204.

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The final partial pressures are then 0.104 atm for COCl are combined and brought to equilibrium at this temperature and at a total pressure of 1.00 atm?

How will the solute tend to distribute itself between the two phases?

One’s first thought might be that some of the solute will migrate from one phase into the other until it is distributed equally between the two phases, since this would correspond to the maximum dispersion (randomness) of the solute.

The biochemical formation of a disaccharide (double) sugar from two monosaccharides is exemplified by the reaction fructose glucose-6-phosphate → sucrose-6-phosphate (Sucrose is ordinary table sugar.) To what volume should a solution containing 0.050 mol of each monosaccharide be diluted in order to bring about 5% conversion to sucrose phosphate?

Solution: The initial and final numbers of moles are as follows: It often happens that two immiscible liquid phases are in contact, one of which contains a solute.

## Comments Solving Equilibrium Problems

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Thus a 0.10M solution of acetic acid is 1.3% ionized, while in a 0.01M solution, 4.3% of the HAc molecules will be dissociated.…

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Example Problems. Problem #1. When 0.40 moles of PCl5 is heated in a 10.0 L container, an equilibrium is established is which 0.25 moles of Cl2 is present.…

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Calculate the value of the Equilibrium Constant for this reaction at 200°C. The solution for this type of problem is simply writing out the Keq expression, filling in.…

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Method to follow in finding numerical solutionsof equilibrium problems. The following. of moles of each substance that appear in the chemical equation. The.…