*Because the equilibrium constant is small, we know that x will be rather small compared to 0.124, so the above relation can be approximated by which gives x = 0.0225.*To see how good this is, substitute this value of x into the denominator of the original equation and solve again: This time, solving for x gives 0.0204.

The final partial pressures are then 0.104 atm for COCl are combined and brought to equilibrium at this temperature and at a total pressure of 1.00 atm?

How will the solute tend to distribute itself between the two phases?

One’s first thought might be that some of the solute will migrate from one phase into the other until it is distributed equally between the two phases, since this would correspond to the maximum dispersion (randomness) of the solute.

The biochemical formation of a disaccharide (double) sugar from two monosaccharides is exemplified by the reaction fructose glucose-6-phosphate → sucrose-6-phosphate (Sucrose is ordinary table sugar.) To what volume should a solution containing 0.050 mol of each monosaccharide be diluted in order to bring about 5% conversion to sucrose phosphate?

Solution: The initial and final numbers of moles are as follows: It often happens that two immiscible liquid phases are in contact, one of which contains a solute.

## Comments Solving Equilibrium Problems

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